(2x^2+x)*(x+1)=1

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Solution for (2x^2+x)*(x+1)=1 equation: 


Simplifying
(2x2 + x)(x + 1) = 1

Reorder the terms:
(x + 2x2)(x + 1) = 1

Reorder the terms:
(x + 2x2)(1 + x) = 1

Multiply (x + 2x2) * (1 + x)
(x(1 + x) + 2x2 * (1 + x)) = 1
((1 * x + x * x) + 2x2 * (1 + x)) = 1
((1x + x2) + 2x2 * (1 + x)) = 1
(1x + x2 + (1 * 2x2 + x * 2x2)) = 1
(1x + x2 + (2x2 + 2x3)) = 1

Combine like terms: x2 + 2x2 = 3x2
(1x + 3x2 + 2x3) = 1

Solving
1x + 3x2 + 2x3 = 1

Solving for variable 'x'.

Reorder the terms:
-1 + 1x + 3x2 + 2x3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1x + 3x2 + 2x3 = 0

The solution to this equation could not be determined.

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